多項式(5)
Author: 藍邦偉  老師
Date: 28 12 月 2012

f(x)>0之解應為1<x<2或x>3

f(x)=-(x-1)(x-2)²(x-3)⇒不和

滿足題意的最低次多項式f(x)=(x-1)(x-2)²

三次多項式的圖形不可能完全在x軸的上方

$ 滿足題意的最低次多項式應為 $

n = 0 (slider from 0 to 5, step 1)
A = Point(xAxis)
B = Point(xAxis)
C = Point(xAxis)
D = (3.26, 1.24)
f_1 = Polynomial({A, B, C, D})
f_2(x) = -(x - 1) * (x - 2)^(2) * (x - 3)
f_3(x) = (x - 1) * (x - 2)^(2)
poly1, a, b, c, d = Polygon(Corner[1], Corner[2], Corner[3], Corner[4])
E = (-6.66, -0.28)
E_1: E + (0.6, 0)
E_3: E + (0, 0.5)
E_2: E_1 + E_3 - E
poly2, e, e_1, e_2, e_3 = Polygon(E, E_1, E_2, E_3)
u = Vector((-1, 0), (x(Corner[2]), 0))
v = Vector((0, y(Corner[1])), (0, y(Corner[3])))