函數的鏡射
Author: 藍邦偉　老師

平移量

單位向量

座標軸

x

y

z

$ x $

$ y $

$ 函數的鏡射 $
$以\;y\;軸為對稱軸$

$ O $

α = 1.5707963267948966 rad (slider from 90*° to 270*°, step 0.01*°)
β = 1.5707963267948966 rad (slider from If[false, 90*°, 0*°] to If[false, 90*°, 360*°], step 0.1*°)
O = (10, 1)
Z_{unit}: O + (0, sin(β))
w = Vector(O, Z_{unit})
Y_{unit}: O + (-1 * sin(α), cos(α) * cos(β))
v = Vector(O, Y_{unit})
List: {-3, -2, -1, -0.5, 0, 0.5, 1, 2, 3}
n = 5 (slider from 1 to 8, step 1)
h = Element(List, n)
B_d: O + (-3 - h) * v
B_c: O + (3 - h) * v
B_a: O + 6 * w + (-3 - h) * v
X_{unit}: O + (cos(α), sin(α) * cos(β))
u = Vector(O, X_{unit})
L = 7.5 (slider from 1 to 10, step 1)
y_{AXIS} = Vector(O - L * v, O + L * v)
z_{AXIS} = Vector(O - L * w, O + L * w)
x_{Axis} = Vector(O - L * u, O + L * u)
c = false
d = true
Q_2: 0.2 * Corner[2] + 0.8 * Corner[1]
Q_3: (x(Q_2), y(Corner[3]))
g = Segment(Q_2, Q_3)
poly1, h_1, q_1, q_4, i = Polygon(Corner[1], Q_2, Q_3, Corner[4])
u_{y'} = Vector((x(Q_2), y(O)), (x(Corner[2]), y(O)))
a = 0.5 (slider from 0.1 to 5, step 0.1)
c_1 = CurveCartesian(x(O + (-h + 2 * a * t) * v + a * t^(2) * w), y(O + (-h + 2 * a * t) * v + a * t^(2) * w), t, -10, 10)
B_b: B_a + B_c - B_d
poly2, b, e, f, j = Polygon(B_d, B_c, B_b, B_a)
text4: "$ y=" + (LaTeX[If[a ≠ 1, FractionText[1 / (4 * a)], ""]]) + "\;(x" + (LaTeX[If[h > 0, "-", "+"]]) + "" + (LaTeX[FractionText[abs(h)]]) + ")² $"
A = (1.1143797346475544, 7.291361386292655)
text5: "$ y=" + (LaTeX[If[a ≠ 1, FractionText[1 / (4 * a)], ""]]) + " \;(x" + (LaTeX[If[h > 0, "+", "-"]]) + "" + (LaTeX[FractionText[abs(h)]]) + ")²$"