$ 一次有理因式檢驗(牛頓)定理 $

$ 若\;px-q\;|\;f(x) ，\;則：\;p\;|\;1,\;q\;|\;6$

$ ⇒p=±1,q=±1,±2,±3,±6 $

$ (x±1),\;(x±2),\;(x±3),\;(x±6)可能為f(x)的一次有理因式 $

$ 請輸入你找到的因式： $

1

s = 1 (slider from 1 to 12, step 1)
f_1(x) = x + 1
f_2(x) = x + 2
f_3(x) = x + 3
f_4(x) = x + 4
f_5(x) = x + 5
f_6(x) = x + 6
f_{-2}(x) = x - 2
f_{-3}(x) = x - 3
f_{-4}(x) = x - 4
f_{-5}(x) = x - 5
f_{-6}(x) = x - 6
f_{-1}(x) = x - 1
F_1 = Expand(f_1(x) * f_2(x) * f_3(x))
text1: "$f(x)= " + (LaTeX[F_1]) + " $"
inputBox1 = Textfield()