Author: 1
Date: 1 11 月 2013

$A$

$B$

$C$

$C'$

1

\sqrt2

1

\sqrt2

1

1

\left\lbrace\begin{array}{ll} sin45°=\frac{1}{\sqrt2} \ cos45°=\frac{1}{\sqrt2} \ tan45°=1\\;\cot45°=1\\;\sec45°=\sqrt2\\;\csc45°=\sqrt2 \end{array}   \right.\ 

$45°$

$45°$

45°的三角函數值

C

C'

t0 = 0 (slider from 0 to 1, step 0.0010)
A = (5.2, 1.24)
A_0: (x(Corner[1]), y(A))
t2 = 3 (slider from 0 to 3, step 0.0010)
L_1: y = y(A)
L_2 = OrthogonalLine(A, L_1)
B = Point(L_1)
c = Circle(A, B)
C = Intersect(c, L_2, 2)
s = 0 (slider from 0 to 10, step 1)
D = Intersect(c, L_2, 1)
α = 0 rad (slider from 0 to 360*°, step 0.01*°)
B' = Rotate(B, α, A)
d = CircleArc(A, B, B')
t1 = 0 (slider from 0 to 1, step 0.0010)
A_b: (x(A), y(Corner[1])) + t1 * Vector[(x(A), y(Corner[1])), (x(A), y(Corner[3]))]
A_a: A - 2 * t1 * Vector[A, (x(A), y(Corner[1]))]
C_3: C + (t2 - 1) * Vector[C, B]
B_3: B + (t2 - 2) * Vector[B, A]
A_1: A_0 + t0 * Vector[A_0, (x(Corner[2]), y(A))]
u_0 = Vector(A, A_1)
A_3: A + t2 * Vector[A, C]
A_4: A + t2 * Vector[A, B]
B_4: B + (t2 - 1) * Vector[B, D]
D_4: D + (t2 - 2) * Vector[D, A]
a = false
b = false
a_1 = Segment(B, C)
a_2 = Segment(B, A)
a_3 = Segment(C, A)
a_4 = Segment(D, A)
a_5 = Segment(D, B)
poly1, p, q, r, t = Polygon(Corner[1] + (0.2, 1.6), Corner[1] + (1, 1.6), Corner[1] + (1.4, 4), Corner[1] + (0.2, 4))
β = Angle(A, B, C)
γ = Angle(A, B, D)
E = (-3.36, 5.2)
w = Segment(A_0, A_1)
w_1 = Segment(A, A_3)
w_2 = Segment(C, C_3)
w_3 = Segment(B, B_3)
b_1 = Segment(A, C)
b_2 = Segment(B, C)
w_4 = Segment(A, A_4)
w_5 = Segment(B, B_4)
w_6 = Segment(D, D_4)
b_3 = Segment(A, B)
b_4 = Segment(D, B)
v = Segment((x(A), y(Corner[1])), A_b)
e: a ≟ false
f: b ≟ false
g: a ≟ false
h: b ≟ false
i: a ≟ false
j: b ≟ false
k: a ≟ false
l: b ≟ false