球面距離
Author: 藍邦偉 老師

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X

Y

Z

座標軸

單位向量

xy平面

A

B

球面距離

α = 4.974188368183839 rad (slider from 0 to 6.283185307179586, step 0.017453292519943295)
β = 1.4835298641951802 rad (slider from 0 to 6.283185307179586, step 0.017453292519943295)
O = (2.656320946128923, 3.7258612553484336)
X: O + (cos(α), sin(α) * cos(β))
Y: O + (-sin(α), cos(α) * cos(β))
Z: O + (0, sin(β))
u = Vector(O, X)
v = Vector(O, Y)
w = Vector(O, Z)
L = 4 (slider from 1 to 10, step 1)
a = Vector(O - L * u, O + L * u)
b = Vector(O - L * v, O + L * v)
c = Vector(O - L * w, O + L * w)
X_x: O + L * u
Y_y: O + L * v
Z_z: O + L * w
m = false
d = false
多邊形1, e, f, g, h = Polygon(O + L * u + L * v, O - L * u + L * v, O - L * u - L * v, O + L * u - L * v)
i = false
n = 2 (slider from 1 to 2, step 1)
j = CurveCartesian(x(O + 3 * cos(θ) * u + 3 * sin(θ) * v), y(O + 3 * cos(θ) * u + 3 * sin(θ) * v), θ, 0, 6.283185307179586)
p = Circle(O, 3)
k = CurveCartesian(x(O + 3 / sqrt(2) * cos(θ) * u + 3 / sqrt(2) * sin(θ) * v + 3 / sqrt(2) * w), y(O + 3 / sqrt(2) * cos(θ) * u + 3 / sqrt(3) * sin(θ) * v + 3 / sqrt(2) * w), θ, 0, 6.28319)
C_2: O + 3 / sqrt(2) * w
P_a: O + 3 / sqrt(2) * w + 2 / sqrt(2) * u + 2 / sqrt(2) * v
P_b: O + 3 / sqrt(2) * w + 2 / sqrt(2) * u - 2 / sqrt(2) * v
l = Segment(C_2, O)
s = Segment(C_2, P_a)
q = Segment(C_2, P_b)
r = Segment(P_a, O)
t = Segment(O, P_b)
t_1 = LineBisector(P_a, P_b)
c_1 = Circle(P_a, P_b)
A = Intersect(c_1, t_1, 1)
d_1 = CircleArc(A, P_b, P_a)
B = Intersect(c_1, t_1, 2)
e_1 = CircleArc(B, P_a, P_b)