指數與對數(12)
Author: 藍邦偉　老師

$ p=3^6=729 $

p=729=\sqrt[3]{243}·3^q⇒3^6=3^{\frac{5}{3}+q}

$ ⇒q=3-\frac{5}{3}=\frac{13}{3} $

n = 1 (slider from 1 to 4, step 1)