指數與對數(16)
Author: 藍邦偉　老師

log_a(a⁴b⁴c²)=log_aa⁴+log_ab⁴+log_ac²

$ =4+4log_ab+2log_ac $

又log_a(a³b²c)=log_a1

⇒log_aa³+log_ab²+log_ac=0

⇒3+2log_ab+log_ac=0

⇒2log_ab+log_ac=-3

$ ∴log_a(a⁴bc²)=4+2×(-3)=-2 $

n = 1 (slider from 1 to 8, step 1)