特別角的三角函數(1)
Author: 藍邦偉  老師

特別角的三角函數值(1)  30°

2

2

2

1

 \sqrt{ 3 } 

30°

60°

u = Vector((x(Corner[1.0]), 0.0), (x(Corner[3.0]), 0.0))
v = Vector((0.0, y(Corner[1.0])), (0.0, y(Corner[3.0])))
A = (-2.573963513518711, 0.6543384761853551)
B: A + (sqrt(3.0), 0.0)
C: B + (0.0, 1.0)
a = Segment(A, B)
b = Segment(B, C)
c = Segment(C, A)
r = 2.3 (slider from 1 to 3, step 0.1)
B' = Dilate(B, r, A)
C' = Dilate(C, r, A)
d = Segment(A, B')
e = Segment(A, C')
f = Segment(B', C')
D = Mirror(C, B)
g = Segment(A, D)
h = Segment(B, D)
k = Circle(A, C, D)
n = 2 (slider from 0 to 6, step 1)