特別角的三角函數(3)
Author: 藍邦偉  老師

1

2

 \sqrt{ 3 } 

60°

特別角的正餘弦三角函數值(3) 60°

2

2

O: 0.5 * (Corner[1.0] + Corner[3.0])
r: 0.4 * (y(Corner[4.0]) - y(Corner[1.0]))
c = Circle(O, r)
B: O + (0.0, r)
A = Rotate(B, 120.0*°, O)
C = Rotate(B, 240.0*°, O)
a = Segment(A, C)
b = Segment(C, B)
d = Segment(B, A)
M = Midpoint(A, C)
e = Segment(B, M)
n = 5 (slider from 0 to 5, step 1)
f = Segment(A, M)
t = 0.3684521399154688 (slider from 0.1684521399154688 to 3.3, step 0.1)
g: x = t
D = Intersect(g, d)
E = Intersect(f, g)
多邊形1, e_1, a_1, d_1 = Polygon(A, D, E)